问题:SUM(n) = 1 + 2 + 3 + ... + n写个算法
回答:
#include<stdio.h>
int main(){ int n,sum; while(scanf("%d",&n)!=EOF) { if(n%2==0) //oushu sum=n/2*(n+1); else sum=(n+1)/2*n; //jishu printf("%d\n\n",sum); } return 0;}本文共 259 字,大约阅读时间需要 1 分钟。
问题:SUM(n) = 1 + 2 + 3 + ... + n写个算法
回答:
#include<stdio.h>
int main(){ int n,sum; while(scanf("%d",&n)!=EOF) { if(n%2==0) //oushu sum=n/2*(n+1); else sum=(n+1)/2*n; //jishu printf("%d\n\n",sum); } return 0;}转载于:https://www.cnblogs.com/benchao/p/4478289.html